Fcu = 25 N/mm Fy = 360
N/mm
qu = Qu / ( b*d ) qall = 0.24 √( Fcu
/γc) = 0.98 N/mm2
Wall
|
Ult. Shear
|
Breadth
|
Depth
|
Qu
|
As
|
no. of
|
Stirrups
|
Notes
|
||
Qu (kN)
|
b (mm)
|
d (mm)
|
(N/mm2)
|
S
|
bran.
|
|||||
1
|
378.2
|
300
|
3850
|
0.327
|
min
|
2
|
6
|
f
|
12
|
safe
|
2
|
156.51
|
300
|
2450
|
0.213
|
min
|
2
|
6
|
f
|
12
|
safe
|
3
|
208.53
|
300
|
2750
|
0.253
|
min
|
2
|
6
|
f
|
12
|
safe
|
4
|
280.77
|
300
|
3770
|
0.248
|
min
|
2
|
6
|
f
|
12
|
safe
|
5
|
225.04
|
300
|
2750
|
0.273
|
min
|
2
|
6
|
f
|
12
|
safe
|
6
|
47.04
|
300
|
2150
|
0.073
|
min
|
2
|
6
|
f
|
12
|
safe
|
7
|
26.29
|
300
|
1350
|
0.065
|
min
|
2
|
6
|
f
|
12
|
safe
|
8
|
122.76
|
300
|
2580
|
0.159
|
min
|
2
|
6
|
f
|
12
|
safe
|
9
|
27.53
|
300
|
1350
|
0.068
|
min
|
2
|
6
|
f
|
12
|
safe
|